Regardless of which version of Words with Friends you use on Android or iOS, you can access built-in features such as Word Radars and Swap + Powerups. These tools are considered by most die-hard punters as fraud, especially since they can not be used by everyone. There is, however, a function that everyone has access to which you can count on against everyone.
The function in question is called "Tile Bag" and since my memory is part of Words with Friends. With this built-in tool, you can see exactly which tiles are left without revealing your opponent's letters. If you have ever played Scrabble, you will recognize this feature as a "letter distribution" list displayed on the game board itself.
When you play Scrabble, you can use the list on the map to determine which letters you are using. The opponent can have and what you can get. The same concept applies to Words with Friends, except that you do not have to reference the board and your rack itself to calculate what is left in your pocket. It takes the work off of you, but does nothing that you can not do just by knowing which letter tiles the game contains.
Tiles Available in Words with Friends
The word distribution in Words with Friends is slightly different compared to Scrabble. Here is a reference to how many letters are shown in bold, with each tile's point value in parentheses. While Scrabble has 1
- A = 9 (each worth 1 point)
- B = 2 (each worth 4 points)  C = 2 (each worth 4 points)
- D = 5 (each worth 2 points)
- E = 13 (each worth 1 point)
- F = 2 (each worth 4 points)
- G = 3 ( worth 3 points each)
- H = 4 (each worth 3 points)
- I = 8 (each worth 1 point) point by point)
- J = 1 (Value 10 points)
- K = 1 (value 5 points)
- L = 4 (value 2 points each)
- M = 2 (each worth 4 points)
- N = 5 (each worth 2 points)
- O = 8 (each worth 1 point)
- P = 2 (each worth 4 points)
- Q = 1 (each worth 10 points)
- R = 6 (each worth 1 point)
- S = 5 (each worth 1 point)
- T = 7 (Who t 1 point per year) h)
- U = 4 (each worth 2 points)
- V = 2 (each worth 5 points)
- W = 2 (each 4 Worth points)
- X = 1 (value 8 points)
- Y = 2 (value 3 points each)
- Z = 1 (value 10 points)
- BLANK = 2 (worth 0 points each)
As previously mentioned, the Tile Pocket is one of the features in Zyngas Words with Friends that you can access, regardless which version of the game you are playing. On your iPhone or Android device, it works in Words with Friends 2 ( Android | iOS), Words with Friends Classic (Android | iOS), and Words with Friends (Android | iOS).
If You Have When a game is open, whether it's against a friend or random opponent, the practice AI, a WordMaster, or a Lightning Round team, tap the "More" tab in the lower left corner and then choose "Tile Bag" from the list of options.
When the Tile Bag opens, it shows you everything that has not yet been played on the board. It also omits what is already in your current mailbox. All tiles that are on your opponent's existing rack are shown here as not yet played. This means that there is no way to decipher the letters they have or do not have exactly.
Another clue is that the "# letters" remaining directly above your rack do not match the available tiles in the tile. The number displayed above your playing field indicates the total number of pieces left in the pocket for you want to draw . The stones possessed by your opponent are not included. So the number above your rack is always seven less than the one shown by the tote bag.
Using Towels More Effectively
Seeing which tiles are left in the game when you first start the game is pretty pointless. Just show everything you do not have on your rack. In my opinion, using the Tile Bag in the first half of a game is not at all helpful. However, once you have exceeded this half-life, this is a great tool. You can see later if you can play a certain word and which high quality letters are not on the board yet.
Just like Scrabble, Words with Friends defense is just as important as the insult. The Tile Bag can help you figure out if you should leave a good move on the board that your opponent may be able to exploit. It can also help you decide if you should play a word blocking any movement of the opponent.
Let's say there is a rating square with three words (TW) that is available from a I on the board is. The Q was recently used at the blackboard to spell QI . The second best you can hope for is XU for a total of 51 points or . XI for 50 points, but has a X been played? A quick glance at the board says no, and the Tile Bag confirms this.
In the example screenshots above, we see that there are still 19 letters in the bag but a total of 26 letters, counting the letters on the rack of our opponent. What are the chances that our opponent will already have the X ready to play?
To find out, we place the X as one of the letters on his rack. That leaves us with 25! (25 faculty) digits to set the other letters. With seven seats for the X on the opponent's rack we have 7 * 25! possible combinations. There are 26! (26 faculties) Total arrangement of the letters in 26 places, the probability would be 7 * 25! / 26! or a 26.9% chance that they have the tile X as one of the seven possibilities on their easel.
To replicate this formula yourself, if a tile in the tile pocket has a "1" next to it. Just take the number of possible letters on the frame (R) and multiply this by the total number of tiles displayed in the tile minus 1 (p !). Then divide your answer by the total number of tiles in the tile bag Tile Bag (T!).
If you do not know how to calculate this with faculty numbers, copy your formula into Google Search and it will display the answer for you. In our case we only have 7 * 25! / 26! in Google, which gave us the 26.9% answer. If there were still 13 pieces left in the pocket and on the opponent's rack, we would be 7 * 12! / 13! At Google, they get a 53.8 percent chance to get the tile X .
All of this, of course, implies that they pulled all seven pieces right after their last move, which probably did not happen. The truth is, they could have pulled X in their first round and saved it all the time. If you are better at math than me, you can probably do better calculations to show a more accurate probability that they have the X or not. (If yes, share!)
Example 2: Calculate if your opponent may have a non-rare letter.
If we use the same board as above, then we want to determine the probability that our opponent has one. H on her easel? With a total of 26 tiles we can not see, we are interested in three of them because there are three H tiles in the Tile Bag. For this we use a slightly different formula, which can also be used to find the answers in Example 1 above, ie 7 * 25! / 26! would look like this:
- 1- (25 select 7) / (26 select 7)
To explain this a little better, you would take the total number of tiles displayed in the tile less the amount next to it that you are interested in (S) and then the number of tiles on your frame (R). Divide the answer by the total number of tiles in the Tile (T) and select the number of tiles on your shelf (R). Then take this answer and subtract it from 1.
- 1- (S choose R) / (T choose R)
If I do not explain this well enough, I'm sorry because my binomial theorem and my binomial coefficient capabilities are rusty at best , All you have to do is use the formula above as a reference and enter it in Google to get the answer.
Back to our scenario H there are three tiles H and a total of 26 platelets in the slide bag. We would use the Formula 1- (23 choose 7) / (26 select 7) to get 0.627 or a 62.7% chance that they already have a H on their rack. That's a high chance. So suppose they have a H which may leave two of them we can draw.
With the findings obtained above, we can calculate the probability that we will have H in our next round, if we believe they have one on their rack. Suppose we know that we want to play ZEINS with four letters from our rack by 48 points. There are currently 19 letters in the bag that we can draw. So our equation would be 1- (17 choose 4) / (19 choose 4) for .386 or a 38.6% chance that one of the letters we draw would be a H tile.
As you can see in the screenshots above, we used the chance to get the H since 38.6% had better chances than one in three lucky ones! You can also use this probability formula to determine how many letters you need to play in order to have a better chance of getting the letter you want when drawing. Playing five letters would have increased our chances to 46.8%, and six letters would have given us 54.4% on reaching H .
If math is not your strong suit, another way is reading your opponent. If you've played several games against them, you've probably developed a sense of what type of player they are. If it's your first game against them, you'll get only a small sample to measure, but it may be enough to determine how they like to play.
For example, if your opponent has already played short two-letter games, words parallel to the board, with a high-quality tile on a premium square, such as ZA JO and / or QI then it is very likely that they will try to play XI XU AX OX etc if they have the ] X and an opening on the blackboard.
So, since you know that a X could be on your rack, you should do everything in your power to ensure that they receive the least amount of potential points when they come to playing it – even if it means ruining your odds on a word with high score, if you were to actually pull the X later. If you have a good score, that may not matter and you take the risk. Using the tiled bag can help you figure out what could happen.
If your opponent tends to play very long words, he may not care to place a two-letter word with X a premium place – even if it means more points. Again, it may be worthwhile to leave this part of the board open to see if you can grab X if it is still available.
As you can see above, we have According to my ZEINS train the opponent actually saw the X already. With a 53.8% chance that they already have it, it's not surprising, and I did not want to block the move as my TIMES was 48 points and nearly nullified their 51 points. I have a huge buffer in the total score, so I did not care about that at all.
Practice and refine your skills in tile bag advantage. Although Words with Friends removes this feature, you can do it all manually by looking at what has already been played on the board, what's on your rack, and what's missing from the 104 tiles. So you would do it in a good old fashioned Scrabble board game, though your mental calculations need to be rough estimates when time is a factor.
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